The number of boys and girls in a class are in the ratio 5 : 4. If the number of boys is 9 more than the number of girls, then number of boys is 9.
False
Let the number of boys be 5x and the number of girls be 4x.
According to the question, – 5x – 4x = 9 => x = 9
Hence, number of boys = 5 x 9 = 45
The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3 :2. Find their present ages.
Sum of the digits of a two-digit number is 11. The given number is less than the number obtained by interchanging the digits by 9. Find the number.
In questions 16 to 32, fill in the blanks to make each statement true.
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Any value of the variable, which makes both sides of an equation equal, is known as a———–of the equation.
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Two numbers differ by 40. When each number is increased by 8, the bigger becomes thrice the lesser number. If one number is x, then the other number is (40 – x).
The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3 :2. Find their present ages.
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(a) positive (b) negative (c) one (d) zero
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The share of A when Rs 25 are divided between A and B, so that A gets Rs 8 more than B, is——–.
When 9 is subtracted from the product of p and 4, the result is 11. The value of p is—-.
When 9 is subtracted from the product of p and 4, the result is 11. The value of p is—-.
Shikha’s present age is p years. Reemu’s present age is 4 times the present age of Shikha. After 5 years, Reemu’s age will be 15p years.
In a 2-digit number, the unit’s place digit is x. If the sum of digits be 9, then the number is (10x – 9).