Shikha’s present age is p years. Reemu’s present age is 4 times the present age of Shikha. After 5 years, Reemu’s age will be 15p years.
False
Given, Shikha's present age = pyr
Then, Reemu's present age = 4 x (Shikha’s present age) = 4pyr After 5 yr, Reemu's age = (4p+5)yr
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Hamid has three boxes of different fruits. Box A weighs 
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A and B are together 90 years old. Five years ago, A was thrice as old as B was. Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years, respectively.
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Sum of the digits of a two-digit number is 11. The given number is less than the number obtained by interchanging the digits by 9. Find the number.
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(c) commutativity (d) associativity .
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In questions 16 to 32, fill in the blanks to make each statement true.
Question. 16 In a linear equation, the——— power of the variable appearing in the equation is one.
A and B are together 90 years old. Five years ago, A was thrice as old as B was. Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years, respectively.
y = –
then y is equal to![-{ left[ frac { 3 }{ 4 }
ight] }^{ 2 }](http://s0.wp.com/latex.php?latex=-%7B+%5Cleft%5B+%5Cfrac+%7B+3+%7D%7B+4+%7D+%5Cright%5D+%7D%5E%7B+2+%7D&bg=ffffff&fg=000&s=0 "-{ left[ frac { 3 }{ 4 }
ight] }^{ 2 }")
(b)![-{ left[ frac { 4 }{ 3 }
ight] }^{ 2 }](http://s0.wp.com/latex.php?latex=-%7B+%5Cleft%5B+%5Cfrac+%7B+4+%7D%7B+3+%7D+%5Cright%5D+%7D%5E%7B+2+%7D&bg=ffffff&fg=000&s=0 "-{ left[ frac { 4 }{ 3 }
ight] }^{ 2 }")
![{ left[ frac { 3 }{ 4 }
ight] }^{ 2 }](http://s0.wp.com/latex.php?latex=%7B+%5Cleft%5B+%5Cfrac+%7B+3+%7D%7B+4+%7D+%5Cright%5D+%7D%5E%7B+2+%7D&bg=ffffff&fg=000&s=0 "{ left[ frac { 3 }{ 4 }
ight] }^{ 2 }")
(d)![{ left[ frac { 4 }{ 3 }
ight] }^{ 2 }](http://s0.wp.com/latex.php?latex=%7B+%5Cleft%5B+%5Cfrac+%7B+4+%7D%7B+3+%7D+%5Cright%5D+%7D%5E%7B+2+%7D&bg=ffffff&fg=000&s=0 "{ left[ frac { 4 }{ 3 }
ight] }^{ 2 }")
, then x=
.
+1 (b) y + 
-4 =
, then the numerical value of 2x – 7 is
(b)
x-2=5-
x,then x=——-.