Chemistry

Thermodynamics

Question:

Which quantity out of ΔrG and ΔrG ° will be zero at equilibrium?

Answer:

Gibbs energy for a reaction in which all reactants and products are in standard state. ΔrG ° is related to the equilibrium constant of the reaction as follows
ΔrG = ArG ° + RT In K
At equilibrium, 0 = ΔrG ° + RT In A ({ΔrG = 0) or       ΔrG ° =-RT lnK
ΔrG ° = 0 when K= 1
For all other values of K, ArG ° will be non-zero.

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Thermodynamics

Q 1.

Consider the following reaction between zinc and oxygen and choose the correct options out of the options given below:
2Zn(s) + 02(g) → 2ZnO(s); ∆H=-693.8 kJ mol-1
(i) The enthalpy of two moles ZnO is less than the total enthalpy of two moles of Zn and one mole of oxygen by 693.8 kJ.
(ii) The enthalpy of two moles of ZnO is more than the total enthalpy of two moles of Zn and one mole of oxygen by 693.8 kJ.
(iii) 8 kJ mol -1 energy is evolved in the reaction.
(iv) 693.8 kJ mol-1 energy is absorbed in the reaction.

Q 2.

From thermodynamic point of view, to which system the animals and plants belong?

Q 3.

Predict the sign of  âˆ†S for the following reaction  heat
CaCO3 (s) ———> CaO(s) + CO2(g)

Q 4.

When is bond energy equal to bond dissociation energy ?

Q 5.

Give reason for the following:
(a)Neither q nor w is a state function but q + w is a state function.
(b)A real crystal has more entropy than an ideal crystal.

Q 7.

The entropy change can be calculated by using the expression ∆S = q rev / T.  When water freezes in a glass beaker, choose the correct statement amongst the following:

When water freezes in a glass beaker, choose the correct statement amongst the following:

(a) ∆S(system) decreases but ∆S(surroundings) remains the same.
(b) ∆S(system) increases but ∆S(surroundings) decreases.
(C) ∆S(system) decreases but ∆S(surroundmgs)  increases.
(d) ∆S(system) decreases but ∆S(surroundings) also decreases.

Q 8.

The spontaneity means, having the potential to proceed without the assistance of external agency. The processes which occur spontaneously are
(a) flow of heat from colder to warmer body.
(b) gas in a container contracting into one comer.
(c) gas expanding to fill the available volume.
(d) burning carbon in oxygen to give carbon dioxide.

Q 9.

Define extensive properties.

Q 10.

What is the condition for spontaneity in terms of free energy change?

Q 11.

Define the following:
(i) First law of thermodynamics.
(ii) Standard enthalpy of formation.

Q 12.

In an exothermic reaction, heat is evolved, and system loses heat to the surroundings. For such system
(a) qP will be negative                                                              
(b) ∆γHwill be negative
(c) qp will be positive                                                                
(d) ∆γHwill be positive.

Q 13.

ncert-solutions-for-class-11-chemistry-chapter-6-thermodynamics-25

Q 14.

What is the enthalpy of formation of the most stable form of an element in its standard state?

Q 15.

Heat capacity (CP) is an extensive property but specific heat (c) is an intensive property. What will be the relation between Cp and c for 1 mol of water?

Q 16.

When two moles of C2H6(g) are burnt, 3129 kj of heat is liberated. Calculate the heat of formation of C2H6(g). ∆fH for  C02(g) and  H20(l) are-393.5 and -286 kj mol-1  respectively.

Q 17.

ncert-solutions-for-class-11-chemistry-chapter-6-thermodynamics-31

Q 18.

Q 19.

ncert-solutions-for-class-11-chemistry-chapter-6-thermodynamics-23

Q 20.

Q 21.

Calculate the number of kj of heat necessary to raise the temperature of 60 g of aluminium from 35 °C to 55 °C. Molar heat capacity of Al is 24  J mol-1 K-1.

Q 22.

How are internal energy change, free energy change and entropy change are related to one another?

Q 23.

Q 24.

A sample of 1.0 mol of a monoatomic ideal gas is taken through a cyclic process of expansion and compression as shown in the figure. What will be the value of ΔHfor the cycle as a whole?

ncert-exemplar-problems-class-11-chemistry-chapter-6-thermodynamics-16

Q 25.

What is a spontaneous change? Give one example.

Q 26.

The enthalpy of atomisation for the reaction CH4(g) → C(g) + 4H(g) is 1665 kJ mol-1. What is the bond energy of C – H bond?

Q 27.

Given : N2(g) + 3H2(g) ————> 2NH3(g); ∆r H  = -92.4 kj mot-1  What is the standard  enthalpy of formation of NH3 gas?

Q 28.

Q 29.

What is the enthalpy change for an adiabatic process?

Q 30.

What are the units of entropy?

Q 31.

During complete combustion of one mole of butane, 2658 kJ of heat is released. The thermochemical reaction for above change is
ncert-exemplar-problems-class-11-chemistry-chapter-6-thermodynamics-1

Q 32.

Thermodynamics mainly deals with
(a) interrelation of various forms of energy and their transformation front one from  to another.
(b) energy changes in the processes which depend only on initial and final states of the microscopic system containing a few molecules.
(c) how and at what rate these energy transformations are carried out.
(d) the system in equilibrium state or moving from one equilibrium state to another equilibrium state.

Q 33.

One mole of acetone requires less heat to vapourise than 1 mol of water. Which of the two liquids has higher enthalpy of vapourisation?

Q 34.

Enthalpy is an extensive property. In general, if enthalpy of an overall reaction A→B along one route is ∆rH and ∆rH1, ∆rH2, ∆rH3 …. represent enthalpies of intermediate reactions leading to product B. What will be the relation between ∆rH for overall reaction and ∆rH1, ∆rH2….. etc. for intermediate reactions.

Q 35.

Enthalpy of combustion of carbon to carbon dioxide is – 393.5 J mol-1   .Calculate the heat released upon formation of 35.2 g of  C02  from carbon and oxygen gas.

Q 36.

What do you mean by entropy?

Q 37.

What is an adiabatic process?

Q 38.

Consider the reactions given below. On the basis of these reactions find out which of the algebraic relations given in options (a) to (d) is correct?
(i) C(g) + 4H(g) → CH4(g); ∆rH= kJ mol-1
(ii) C(graphite, s) + 2H2(g) → CH4(g); ∆rH = y kJ mol 1
(a) x = y                                   (b) x = 2y                     (c)x >y         (d)x< y

Q 39.

For an ideal gas. the work of reversible expansion under isothermal condition 1.0 mol of an ideal gas is expanded isothermally and reversibly to ten times of its original volume, in two separate experiments. The expansion is carried out at 300 K and at 600 K respectively. Choose the correct option.
can be calculated by using expression w = -nRT In Vf / Vi A sample containing
(a) Work done at 600 K is 20 times the work done at 300 K.
(b) Work done at 300 K is twice the work done at 600 K
(c) Work done at 600 K is twice the work done at 300 K.
(d) ∆U= 0 in both cases.

Q 40.

Q 41.

For an isolated system∆U = 0; what will be ∆S?

Q 42.

At what temperature entropy of a substance is zero?

Q 43.

Define intensive properties.

Q 44.

1 g of graphite is burnt in a bomb calorimeter in excess of oxygen at 298 K and 1 atmospheric pressure according to the equation C(graphite) + 02 (g) —> C02 (g) During the reaction, temperature rises from 298 K to 299 K. If the heat capacity of the bomb calorimeter is 20.7 kJ/K, what is the enthalpy change for the above reaction at 298 K and 1 atm?

Q 45.

Why standard entropy of an elementary substance is not zero whereas standard enthalpy of formation is taken as zero?

Q 46.

Many thermodynamically feasible reactions do not occur under ordinary conditions. Why?

Q 47.

Increase in enthalpy of the surroundings is equal to decrease in enthalpy of the system. Will the temperature of system and surroundings be the same when they are in thermal equilibrium?

Q 48.

The difference between Cp and Cv can be derived using the empirical relation H = U + pV. Calculate the difference between Cp and Cv for 10 moles of an ideal gas.

Q 49.

Calculate the enthalpy of the reaction:
N204(g) + 3CO(g) ———->N20(g) + 3CO2(g)
Given that;∆fHCO(g) = – 110 kj mot-1; ∆fHC02(g) = – 393 kj mol-1
∆fHN20(g) = 81 kj mot-1; ∆fN2O4(g) = 9.7 kj mol-1

Q 50.

Calculate the standard enthalpy of formation of CH3OH. from the following data:
(i) CH3OH(l) + 3/2 02 (g) ———-> CO2 (g) + 2H20 (l); ∆rH = – 726kj mol-1
(ii) C(s) + 02(g) —————>C02 (g); ∆cH = -393 kj mol-1
(iii) H2(g) + 1/202(g) —————->H20 (l); ∆fH = -286 kj mol-1