Multiplying two selected 3 digit numbers middle digit 1
1.Select a 3-digit number with a middle digit of 1.
2.Choose a multiplier with the same first two digits, whose third digit sums to 10 with the third digit of the first 3-digit number.
3.The last two digits will be the product of the first digits:___ ___OX or__ ____ ____ ___XX.
4.The third digit from the right will be 2:__ __2___ ___or___ __ __2____ ____.
5.The next digit to the left will be 3 times the first digit of the number (keep carry):_X_________or_______X________.
6.The first digits will be the square of the first digit plus the carry: X______ ____or XX______ _______.
As you determine the digits in the answer from right to left, repeat them to yourself at each step until you have the whole answer.
Example:
1.If the first number is 814, choose 816 as the second number (same first digits,second digits add to 10).
2.4 x 6 = 24 (multiply the first digits) - last two digits:2 4.
3.The third digit from the right is 2:__ ___ ___ __2__ __ _.
4.8 x 3 = 24 (the next digit to the left is 3 times the first digit (keep carry 2):_4 _
5.8x8 = 64; 64 + 2 = 66 ( the first digits are the square of the first digit plus the carry:6 6______ _____,
6.So 814 x 816 = 664224.
See the pattern?
1.If the first number is 317, choose 313 as the multiplier (same first digits, second digits add to 10).
2.7 x 3 = 21 (multiply the first digits) - last two digits: 2 1.
3.The third digit from the right is 2:___ ___ ____2__ ___.
4.3x3 = 9 (the next digit to the left is 3 times the first digit (no carry): _ 9____ _____ _____ ___ __.
5.3x3= 9 (the first digits are the square of the first digit: 9_.
6.So 317 x313 = 99221.
Notes
Vedic Maths - Notes
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