Question 2
Marks : +2 | -2
Pass Ratio : 100%
What is the partial fraction expansion of the proper function X(z)=\\(\\frac{1}{1-1.5z^{-1}+0.5z^{-2}}\\)?
Explanation: First we eliminate the negative powers of z by multiplying both numerator and denominator by z2.
Question 3
Marks : +2 | -2
Pass Ratio : 100%
What is the inverse z-transform of X(z)=log(1+az-1) |z|>|a|?
Explanation: Using the power series expansion for log(1+x), with |x|<1, we have
Question 4
Marks : +2 | -2
Pass Ratio : 100%
What is the partial fraction expansion of X(z)=\\(\\frac{1}{(1+z^{-1})(1-z^{-1})^2}\\)?
Explanation: First we express X(z) in terms of positive powers of z, in the form X(z)=\\(\\frac{z^3}{(z+1)(z-1)^2}\\)
Question 6
Marks : +2 | -2
Pass Ratio : 100%
What is the inverse z-transform of X(z)=\\(\\frac{1}{1-1.5z^{-1}+0.5z^{-2}}\\) if ROC is |z|>1?
Explanation: Since the ROC is the exterior circle, we expect x(n) to be a causal signal. Thus we seek a power series expansion in negative powers of ‘z’. By dividing the numerator of X(z) by its denominator, we obtain the power series
Question 7
Marks : +2 | -2
Pass Ratio : 100%
Which of the following method is used to find the inverse z-transform of a signal?
Explanation: All the methods mentioned above can be used to calculate the inverse z-transform of the given signal.
Question 9
Marks : +2 | -2
Pass Ratio : 100%
What is the proper fraction and polynomial form of the improper rational transform
Explanation: First, we note that we should reduce the numerator so that the terms z-2 and z-3 are eliminated. Thus we should carry out the long division with these two polynomials written in the reverse order. We stop the division when the order of the remainder becomes z-1. Then we obtain
Question 10
Marks : +2 | -2
Pass Ratio : 100%
What is the partial fraction expansion of X(z)=\\(\\frac{1+z^{-1}}{1-z^{-1}+0.5z^{-2}}\\)?
Explanation: To eliminate the negative powers of z, we multiply both numerator and denominator by z2. Thus,