Digital Signal Processing

Design of Optimum Equi Ripple Linear Phase FIR Filters

Question 1
Marks : +2 | -2
Pass Ratio : 100%
The error function E(ω) does not alternate in sign between two successive extremal frequencies.
True
False
Explanation:
The error function E(ω) alternates in sign between two successive extremal frequency, Hence the theorem is called as Alternative theorem.
Question 2
Marks : +2 | -2
Pass Ratio : 100%
If M is the length of the filter, then at how many number of points, the error function is computed?
2M
4M
8M
16M
Explanation:
Having the solution for P(ω), we can now compute the error function E(ω) from
Question 3
Marks : +2 | -2
Pass Ratio : 100%
Which of the following filter design is used in the formulation of design of optimum equi ripple linear phase FIR filter?
Butterworth approximation
Chebyshev approximation
Hamming approximation
None of the mentioned
Explanation:
The filter design method described in the design of optimum equi ripple linear phase FIR filters is formulated as a chebyshev approximation problem.
Question 4
Marks : +2 | -2
Pass Ratio : 100%
Which of the following defines the weighted approximation error?
W(ω)[Hdr(ω)+Hr(ω)]
W(ω)[Hdr(ω)-Hr(ω)]
W(ω)[Hr(ω)-Hdr(ω)]
None of the mentioned
Explanation:
The weighted approximation error is defined as E(ω) which is given as
Question 5
Marks : +2 | -2
Pass Ratio : 100%
If the filter has anti-symmetric unit sample response with M even, then what is the value of Q(ω)?
cos(ω/2)
sin(ω/2)
1
sinω
Explanation:
If the filter has a anti-symmetric unit sample response, then we know that
Question 6
Marks : +2 | -2
Pass Ratio : 100%
Remez exchange algorithm is an iterative algorithm used in error approximation.
True
False
Explanation:
Initially, we neither know the set of external frequencies nor the parameters. To solve for the parameters, we use an iterative algorithm called the Remez exchange algorithm, in which we begin by guessing at the set of extremal frequencies.
Question 7
Marks : +2 | -2
Pass Ratio : 100%
In which of the following way the real valued desired frequency response is defined?
Unity in stop band and zero in pass band
Unity in both pass and stop bands
Unity in pass band and zero in stop band
Zero in both stop and pass band
Explanation:
The real valued desired frequency response Hdr(ω) is simply defined to be unity in the pass band and zero in the stop band.
Question 8
Marks : +2 | -2
Pass Ratio : 100%
If δ2 represents the ripple in the stop band for a chebyshev filter, then which of the following conditions is true?
1-δ2 ≤ Hr(ω) ≤ 1+δ2;|ω|≤ωs
1+δ2 ≤ Hr(ω) ≤ 1-δ2;|ω|≥ωs
δ2 ≤ Hr(ω) ≤ δ2;|ω|≤ωs
-δ2 ≤ Hr(ω) ≤ δ2;|ω|≥ωs
Explanation:
Let us consider the design of a low pass filter with the stop band edge frequency ωs and the ripple in the stop band is δ2, then from the general specifications of the chebyshev filter, in the stop band the filter frequency response should satisfy the condition
Question 9
Marks : +2 | -2
Pass Ratio : 100%
When |E(ω)|≤δ for all frequencies on the dense set, the optimal solution has been found in terms of the polynomial H(ω).
True
False
Explanation:
|E(ω)|≥δ for some frequencies on the dense set, then a new set of frequencies corresponding to the L+2 largest peaks of |E(ω)| are selected and computation is repeated. Since the new set of L+2 extremal frequencies are selected to increase in each iteration until it converges to the upper bound, this implies that when |E(ω)|≤δ for all frequencies on the dense set, the optimal solution has been found in terms of the polynomial H(ω).
Question 10
Marks : +2 | -2
Pass Ratio : 100%
It is convenient to normalize W(ω) to unity in the stop band and set W(ω)=δ2/ δ1 in the pass band.
True
False
Explanation:
The weighting function on the approximation error allows to choose the relative size of the errors in the different frequency bands. In particular, it is convenient to normalize W(ω) to unity in the stop band and set W(ω)=δ2/δ1 in the pass band.