Digital Signal Processing

Design of Linear Phase FIR Filters by Frequency Sampling Method

Question 1
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is introduced in the frequency sampling realization of the FIR filter?
Poles are more in number on unit circle
Zeros are more in number on the unit circle
Poles and zeros at equally spaced points on the unit circle
None of the mentioned
Explanation:
There is a potential problem for frequency sampling realization of the FIR linear phase filter. The frequency sampling realization of the FIR filter introduces poles and zeros at equally spaced points on the unit circle.
Question 2
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Pass Ratio : 100%
What is the frequency response of a system with input h(n) and window length of M?
\\(\\sum_{n=0}^{M-1} h(n)e^{jωn}\\)
\\(\\sum_{n=0}^{M} h(n)e^{jωn}\\)
\\(\\sum_{n=0}^M h(n)e^{-jωn}\\)
\\(\\sum_{n=0}^{M-1} h(n)e^{-jωn}\\)
Explanation:
The desired output of an FIR filter with an input h(n) and using a window of length M is given as
Question 3
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is equal to the value of H(k+α)?
H*(M-k+α)
H*(M+k+α)
H*(M+k-α)
H*(M-k-α)
Explanation:
Since {h(n)} is real, we can easily show that the frequency samples {H(k+α)} satisfy the symmetry condition
Question 4
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Pass Ratio : 100%
What is the relation between H(k+α) and h(n)?
H(k+α)=\\(\\sum_{n=0}^{M+1} h(n)e^{-j2Ï€(k+α)n/M}\\); k=0,1,2…M+1
H(k+α)=\\(\\sum_{n=0}^{M-1} h(n)e^{-j2Ï€(k+α)n/M}\\); k=0,1,2…M-1
H(k+α)=\\(\\sum_{n=0}^M h(n)e^{-j2Ï€(k+α)n/M}\\); k=0,1,2…M
None of the mentioned
Explanation:
We know that
Question 5
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Pass Ratio : 100%
The major advantage of designing linear phase FIR filter using frequency sampling method lies in the efficient frequency sampling structure.
True
False
Explanation:
Although the frequency sampling method provides us with another means for designing linear phase FIR filters, its major advantage lies in the efficient frequency sampling structure, which is obtained when most of the frequency samples are zero.
Question 6
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Pass Ratio : 100%
In the frequency sampling method for FIR filter design, we specify the desired frequency response Hd(ω) at a set of equally spaced frequencies.
True
False
Explanation:
In the frequency sampling method, we specify the frequency response Hd(ω) at a set of equally spaced frequencies, namely ωk=\\(\\frac{2π}{M}(k+\\alpha)\\)
Question 7
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is the correct expression for h(n) in terms of H(k+α)?
\\(\\frac{1}{M} \\sum_{k=0}^{M-1}H(k+α)e^{j2Ï€(k+α)n/M}\\); n=0,1,2…M-1
\\(\\sum_{k=0}^{M-1}H(k+α)e^{j2Ï€(k+α)n/M}\\); n=0,1,2…M-1
\\(\\frac{1}{M} \\sum_{k=0}^{M+1}H(k+α)e^{j2Ï€(k+α)n/M}\\); n=0,1,2…M+1
\\(\\sum_{k=0}^{M+1}H(k+α)e^{j2Ï€(k+α)n/M}\\); n=0,1,2…M+1
Explanation:
We know that
Question 8
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To reduce side lobes, in which region of the filter the frequency specifications have to be optimized?
Stop band
Pass band
Transition band
None of the mentioned
Explanation:
To reduce the side lobes, it is desirable to optimize the frequency specification in the transition band of the filter. This optimization can be accomplished numerically on a digital computer by means of linear programming techniques.
Question 9
Marks : +2 | -2
Pass Ratio : 100%
The linear equations for determining {h(n)} from {H(k+α)} are not simplified.
True
False
Explanation:
The symmetry condition, along with the symmetry conditions for {h(n)}, can be used to reduce the frequency specifications from M points to (M+1)/2 points for M odd and M/2 for M even. Thus the linear equations for determining {h(n)} from {H(k+α)} are considerably simplified.
Question 10
Marks : +2 | -2
Pass Ratio : 100%
In a practical implementation of the frequency sampling realization, quantization effects preclude a perfect cancellation of the poles and zeros.
True
False
Explanation:
In the ideal situation, the zeros cancel the poles and, consequently, the actual zeros of the H(z) are determined by the selection of the frequency samples H(k+α). In a practical implementation of the frequency sampling realization, however, quantization effects preclude a perfect cancellation of the poles and zeros.