Chemical Engineering

Species Material Balances

Question 1
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with a feed of composition 46% C3H7O4, 44% O2 and 10% N2, if 50% of the limiting reagent is converted into product, what is the percentage of O2 in the product?
10
18
38
54
Explanation:
The reaction is 4C3H7O4 + 11O2 -> 12CO2 + 14H2O, => Limiting reagent is O2. Let 100 moles of feed was supplied, => after the reaction, moles of CO2 = 24, moles of H2O = 28, moles of O2 = 22, moles of C3H7O4 = 38, moles of N2 = 10, => percentage of O2 = 18%.
Question 2
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with 10 moles of CH4 and 10 moles of O2, if the extent of reaction is 3, what are the moles of CO2 produced?
3
6
8
12
Explanation:
The chemical reaction is CH4 + 2O2 -> CO2 + 2H2O, => moles of CO2 produced = 3*1 = 3.
Question 3
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with a feed of composition 46% C3H7O4, 44% O2 and 10% N2, if 50% of the limiting reagent is converted into product, what is the percentage of C3H7O4 in the product?
10
16
31
43
Explanation:
The reaction is 4C3H7O4 + 11O2 -> 12CO2 + 14H2O, => Limiting reagent is O2. Let 100 moles of feed was supplied, => after the reaction, moles of CO2 = 24, moles of H2O = 28, moles of O2 = 22, moles of C3H7O4 = 38, moles of N2 = 10, => percentage of C3H7O4 = 31%.
Question 4
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with a feed of composition 46% C3H7O4, 44% O2 and 10% N2, if 50% of the limiting reagent is converted into product, what is the percentage of N2 in the product?
8
18
34
46
Explanation:
The reaction is 4C3H7O4 + 11O2 -> 12CO2 + 14H2O, => Limiting reagent is O2. Let 100 moles of feed was supplied, => after the reaction, moles of CO2 = 24, moles of H2O = 28, moles of O2 = 22, moles of C3H7O4 = 38, moles of N2 = 10, => percentage of N2 = 8%.
Question 5
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with a feed of composition 46% C3H7O4, 44% O2 and 10% N2, if 50% of the limiting reagent is converted into product, what is the percentage of H2O in the product?
15
23
39
51
Explanation:
The reaction is 4C3H7O4 + 11O2 -> 12CO2 + 14H2O, => Limiting reagent is O2. Let 100 moles of feed was supplied, => after the reaction, moles of CO2 = 24, moles of H2O = 28, moles of O2 = 22, moles of C3H7O4 = 38, moles of N2 = 10, => percentage of H2O = 23%.
Question 6
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with a 100 mole feed of composition 46% C3H7O4, 44% O2 and 10% N2, if 50% of the limiting reagent is converted into product, what is the extent of reaction?
1
2
3
4
Explanation:
The reaction is 4C3H7O4 + 11O2 -> 12CO2 + 14H2O, => limiting reagent is O2, => Extent of reaction = (44*0.5 – 44)/(-11) = 2.
Question 7
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with 6 moles of CO and 3 moles of O2 and produced 4 moles of CO2, what is the extent of reaction?
1
2
3
4
Explanation:
The reaction is 2CO + O2 -> 2CO2, => Extent of reaction = (4 – 0)/2 = 2.
Question 8
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with 10 moles of O2 and 10 moles of H2, if the extent of reaction is 5, how many moles of water is produced?
5
10
15
20
Explanation:
The chemical reaction is 2H2 + O2 -> 2H2O, => moles of H2O produced = 5*2 = 10.
Question 9
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with 6 moles of N2 and 9 moles of H2, if 3 moles of NH3 is produced, how many moles of H2 are left at the end?
1.5
3
4.5
6
Explanation:
The reaction is N2 + 3H2 -> 2NH3, => extent of reaction = (3 – 0)/2 = 1.5, => moles of H2 left = 9 – 1.5*3 = 4.5.
Question 10
Marks : +2 | -2
Pass Ratio : 100%
A reactor is supplied with 5 moles of KNO3 and some H2SO4, if the extent of reaction is 2, how many moles of H2SO4 were supplied?
1
2
5
Cannot be determined
Explanation:
Since the final moles of H2SO4 are not given, initial moles cannot be determined.