N2 with pressure 10 atm and H2 with pressure 30 atm, both with volume 10 liter at 27oC are passed into a reactor, how many moles NH3 is produced?
Explanation: The reaction is N2 + 3H2 -> 2NH3, moles of N2 = 10*10/(0.0821*300) = 4, moles of H2 = 30*10/(0.0821*300) = 12, => extent of reaction = (0 – 4)/(-1) = 4, => moles of NH3 = 4*2 = 8.