Chemical Engineering

Flow Rate

Question 1
Marks : +2 | -2
Pass Ratio : 100%
1 mole of Carbon dioxide enters in a reactor at a rate of 0.25 kg/s and leaves it at the rate of 1 kg/s, what are the number of moles of carbon dioxide leaves the reactor?
0.25
0.5
0.75
1
Explanation:
Applying reaction equilibrium equation, 1*0.25 = n*1, => n = 0.25.
Question 2
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is not conserved for the flow of an incompressible liquid in a pipe with variable area?
Mass
Volume
Velocity
Flow Rate
Explanation:
According to the equation of continuity, the product of area and velocity remains constant throughout the pipe, since the area of the pipe is variable, so the velocity if the liquid is variable.
Question 3
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is the unit of flow rate?
Kg/s
Liters/s
Moles/s
All of the mentioned
Explanation:
Mass flow rate = m/t, => unit = kg/s, volumetric flow rate = V/t, => unit = Liters/s, molar rate = n/t, => unit = moles/s.
Question 4
Marks : +2 | -2
Pass Ratio : 100%
The velocity of water in a pipe of area 5 m2 is 10 m/s, what will be the flow rate of water?
25 m3/s
50 m3/s
75 m3/s
100 m3/s
Explanation:
Flow rate = area*velocity = 5*10 = 50 m3/s.
Question 5
Marks : +2 | -2
Pass Ratio : 100%
What is the mass flow rate of a liquid flowing through a pipe of which 100 grams of water was collected in 10 seconds?
0.01 kg/s
0.05 kg/s
0.1 kg/s
0.5 kg/s
Explanation:
mass flow rate = 0.1/ 10 = 0.01 kg/s.
Question 6
Marks : +2 | -2
Pass Ratio : 100%
A liquid of density 0.1 kg/m3 is flowing through a pipe at a rate of 15 kg/s, what will be the area of the pipe if the fluid velocity is 5 m/s?
30 m2
45 m2
75 m2
90 m2
Explanation:
Volumetric flow rate of the liquid = 15/0.1 = 150 m3/s, => Area of pipe = 150/5 = 30 m2.
Question 7
Marks : +2 | -2
Pass Ratio : 100%
What is the volumetric flow rate if 100 kg of water is collected in 10 seconds? (Density of water = 1000 kg/m3)
0.1 m3/s
0.2 m3/s
0.01 m3/s
0.02 m3/s
Explanation:
volume of water collected = 100/1000 = 0.1 m3, => volumetric flow rate = 0.1/10 = 0.01 m3/s.
Question 8
Marks : +2 | -2
Pass Ratio : 100%
A Composition of carbon dioxide, oxygen and nitrogen with mole ratio 1:2:5 with 4 moles of oxygen, enters a reactor with a flow rate of 100 kg/s, the ratio of rates of leaving the reactor of the three is 5:2:1, and 5 moles of nitrogen leaves the reactor, what is the total number of moles leaving the reactor?
6.1
6.2
6.3
6.4
Explanation:
number of moles of carbon dioxide, oxygen and nitrogen are 2, 4 and 10 respectively, let the leaving flow rates of carbon dioxide, oxygen and nitrogen are 5y, 2y and y respectively, => for nitrogen, 10*100 = y*5 => y = 200 kg/s, => for oxygen, 4*100 = 400*n => n = 1, for carbon dioxide, 2*100 = 1000*n => n = 0.2, => total number of moles leaving the reactor = 5 + 1 + 0.2 = 6.2.
Question 9
Marks : +2 | -2
Pass Ratio : 100%
A liquid is flowing through a pipe of cross section 4 m2 at a rate of 4 kg/s, at a point pipe is divided into two pipes of areas of equal areas, what will be the ratio of flow rate in both the pipes?
1:3
1:1
1:2
2:3
Explanation:
Since areas of the pipes are equal, by continuity equation flow will divide equally in the pipes, so their ratio will be 1:1.
Question 10
Marks : +2 | -2
Pass Ratio : 100%
10 moles of oxygen divides and enters two reactors flow rate 45 kg/s and leaves the reactors at the flow rates of 6 kg/s and 9 kg/s, what are number of moles of oxygen that leaves the reactor with 9 kg/s?
180
450
60
90
Explanation:
Let number of moles entering and leaving the second reactor be n1 and n2 respectively, applying reaction equilibrium equation to whole system, => 10*45 = n*(6 + 9), => n = 30, => Applying reaction equilibrium equation to both the reactors separately, => n1*45 = n2*9 => n2 = 5n1, and (10 – n1)*45 = (30 – n2)*6, Solving both equations we get n2 = 90.