Chemical Engineering

Compressibility

Question 1
Marks : +2 | -2
Pass Ratio : 100%
At what temperature, does SO2 with compressibility 2 has pressure 5 atm and molar volume 10 mole/s?
300.5 K
304.5 K
310 K
312.5 K
Explanation:
T = PV/zR = 5*10/(2*0.0821) = 304.5 K.
Question 2
Marks : +2 | -2
Pass Ratio : 100%
What is the compressibility of ideal gases?
1
2
3
4
Explanation:
Compressibility = PV/nRT, but for ideal gases PV = nRT, => Compressibility = 1.
Question 3
Marks : +2 | -2
Pass Ratio : 100%
What is the pressure of CO2 gas with compressibility z = 0.8, if the ideal gas pressure of CO2 is 10 Pa, all other variables are same?
5
8
10
14
Explanation:
Pressure of CO2 = 0.8*10 = 8 Pa.
Question 4
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is true about compressibility of real gases?
Z = 1
Z < 1
Z > 1
Both Z < 1 and Z > 1
Explanation:
For any value of compressibility except 1, the gas is real.
Question 5
Marks : +2 | -2
Pass Ratio : 100%
What is the compressibility of methane with density 10 g/liter at 27oC and 500 atm?
32.5
34.8
39.6
44.1
Explanation:
z = PM/dRT = 500*16/(10*0.0821*300) = 32.5.
Question 6
Marks : +2 | -2
Pass Ratio : 100%
What is the compressibility of neon (molar mass = 20) with density 20 g/liter at 27oC and 100 atm?
2.1
3.5
4
6.8
Explanation:
z = PM/dRT = 100*20/(20*0.0821*300) = 4.
Question 7
Marks : +2 | -2
Pass Ratio : 100%
What is the pressure of H2 with compressibility 0.6, molar volume 5 liter/mole at 27oC?
2.9 atm
5.4 atm
9.6 atm
14.5 atm
Explanation:
P = znRT/V, => P = 0.6*0.0821*300/5 = 2.9 atm.
Question 8
Marks : +2 | -2
Pass Ratio : 100%
What is the compressibility factor of a liquid of molar mass 90 g and density 10 g/liter at 27oC and 2 atm?
0.14
0.39
0.51
0.73
Explanation:
z = PM/dRT = 2*90/(10*0.0821*300) = 0.73.
Question 9
Marks : +2 | -2
Pass Ratio : 100%
What is the compressibility factor of water with density 1 g/liter at 27oC and 1 atm?
0.25
0.59
0.73
0.91
Explanation:
z = PM/dRT = 1*18/(1*0.0821*300) = 0.73.
Question 10
Marks : +2 | -2
Pass Ratio : 100%
What is the pressure of 80 grams of CH4 with compressibility 5, with 10 liter volume at 27oC?
10.5 atm
28.9 atm
44.2 atm
61.5 atm
Explanation:
P = 5*5*0.0821*300/10 = 61.5 atm.