A and B are together 90 years old. Five years ago, A was thrice as old as B was. Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years, respectively.
True
Let the age of A be x yr.
Then, age of S = (90 – x) yr
Five years ago, the age of A = (x- 5) yr
The age of B= 90-x-5 = (85-x)yr
Hence, the ages of A and 8 five years back would be (x – 5) yr and (85 – x) yr, respectively.
The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3 :2. Find their present ages.
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When 9 is subtracted from the product of p and 4, the result is 11. The value of p is—-.
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The value of x, for which the expressions 3x – 4 and 2x + 1 become equal, is
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In questions 16 to 32, fill in the blanks to make each statement true.
Question. 16 In a linear equation, the——— power of the variable appearing in the equation is one.
A and B are together 90 years old. Five years ago, A was thrice as old as B was. Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years, respectively.
y = –
then y is equal to![-{ left[ frac { 3 }{ 4 }
ight] }^{ 2 }](http://s0.wp.com/latex.php?latex=-%7B+%5Cleft%5B+%5Cfrac+%7B+3+%7D%7B+4+%7D+%5Cright%5D+%7D%5E%7B+2+%7D&bg=ffffff&fg=000&s=0 "-{ left[ frac { 3 }{ 4 }
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ight] }^{ 2 }")
![{ left[ frac { 3 }{ 4 }
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(d)![{ left[ frac { 4 }{ 3 }
ight] }^{ 2 }](http://s0.wp.com/latex.php?latex=%7B+%5Cleft%5B+%5Cfrac+%7B+4+%7D%7B+3+%7D+%5Cright%5D+%7D%5E%7B+2+%7D&bg=ffffff&fg=000&s=0 "{ left[ frac { 4 }{ 3 }
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+1 (b) y + 
x-2=5-
x,then x=——-.
+ 30 = 18 has the solution as——–.
