Decomposition Using Functional Dependencies

Question 1
Marks : +2 | -2
Pass Ratio : 100%
F+ is called as the ________ of F
Closure
Sum
Cartesian product
None of the mentioned
Explanation:
F+ is called as the closure of F. It contains all the possible combinations of a functional dependency set in it.
Question 2
Marks : +2 | -2
Pass Ratio : 100%
X→ Y is trivial if?
X ⊂ Y
Y ⊂ X
X ⊇ Y
None of the mentioned
Explanation:
X→ Y is said to be trivial if X is a subset of Y. Thus X ⊂ Y implies X→Y is trivial.
Question 3
Marks : +2 | -2
Pass Ratio : 100%
An instance of a relation that satisfies all real world constraints is known as?
Proper relation
Ideal relation
Perfect relation
Legal relation
Explanation:
A relation that satisfies all the real world constraints is called as a legal relation. An instance of a legal relation is called as a legal instance.
Question 4
Marks : +2 | -2
Pass Ratio : 100%
State true or false: The fourth normal form does not exist and it is instead called as the BCNF.
True
False
Explanation:
The fourth normal form exists and is different from the Boyce Codd normal form which is called as BCNF.
Question 5
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is not a condition for the third normal form in the case of XY?
X→ Y is trivial
X is the superkey for R
Each attribute in Y-X is a candidate key for R
Each attribute in X-Y is a candidate key for R
Explanation:
Each attribute in X-Y is a candidate key for R is not a necessary condition for the third normal form in the case of X → Y. X→Y is trivial and X is the superkey of R are necessary conditions for the third normal form.
Question 6
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is not a condition for X→ Y in Boyce codd normal form?
X → Y is trivial
X is the superkey for the relational schema R
Y is the superkey for the relational schema R
All of the mentioned
Explanation:
Y does not need to be a superkey of the relation for the given functional dependency to satisfy BCNF. X→ Y must be trivial and X must be the superkey of the relation R.
Question 7
Marks : +2 | -2
Pass Ratio : 100%
If K → R then K is said to be the _______ of R
Candidate key
Foreign key
Super key
Domain
Explanation:
If K → R then k is said to be the superkey of R i.e. K uniquely identifies every tuple in the relation R.
Question 8
Marks : +2 | -2
Pass Ratio : 100%
State true or false: A functional dependency must first satisfy the second normal form to satisfy the third normal form.
True
False
Explanation:
A functional dependency must first satisfy the second normal form to satisfy the third normal form. The second normal form must in turn satisfy first normal form.
Question 9
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is used to express database consistency?
Primary keys
Functional dependencies
Check clause
All of the mentioned
Explanation:
Primary keys, Functional dependencies, Check clause are all used to express database consistency.
Question 10
Marks : +2 | -2
Pass Ratio : 100%
X → Y holds on a schema k(K) if?
At least one legal instance satisfies the functional dependency
No legal instance satisfies the functional dependency
Each and every legal instance satisfies the functional dependency
None of the mentioned
Explanation:
X → Y holds on a schema k(K) if each and every legal instance satisfies the functional dependency. Even if one instance does not satisfy the functional dependency X→ Y does not hold on a schema.