Simple Harmonic Motion

Question 1
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The frequency of oscillation for the simple pendulum is
1/2π √L/g
1/2π √g/L
2π √L/g
2π√g/L
Explanation:
The motion of the bob from one extremity to the other is known as beat or swing. Thus one beat = 1/2 oscillation.
Question 2
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The velocity of a particle moving with simple harmonic motion is . . . . at the mean position.
zero
minimum
maximum
none of the mentioned
Explanation:
At mean the value of x = 0. Therefore, it is maximum at mean position.
Question 3
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When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as
simple pendulum
torsional pendulum
compound pendulum
second’s pendulum
Explanation:
When a rigid body is suspended vertically, and it oscillates with a small amplitude under the action of the force of gravity, the body is known as compound pendulum. Thus the periodic time of a compound pendulum is minimum when the distance between the point of suspension and the centre of gravity is equal to the radius of gyration of the body about its centre of gravity.
Question 4
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The frequency of oscillation of a compound pendulum is
1/2π √g.h/k2G +h2
1/2π √k2G +h2/g.h
2π√g.h/k2G +h2
2π√k2G +h2/g.h
Explanation:
We know that the periodic time,
Question 5
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The maximum acceleration of a particle moving with simple harmonic motion is
ω
ω.r
ω2.r
ω2/r
Explanation:
Acceleration, aN = ω2.rcosθ = ω2.r.
Question 6
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The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by
ω √r2 − x2
ω √x2 − r2
ω2 √r2 − x2
ω2√x2 − r2
Explanation:
Velocity of any particle vN = vsinθ = ω.rsinθ = ω √r2 − x2.
Question 7
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The centre of percussion is below the centre of gravity of the body and is at a distance equal to
h / kG
h.kG
h2/kG
k2G/h
Explanation:
The centre of oscillation is sometimes termed as centre of percussion. It is defined as that point at which a blow may be struck on a suspended body so that the reaction at the support is zero. The centre of percussion is below the centre of gravity and at a distance k2G/h. The distance between the centre of suspension and the centre of percussion is equal to the equivalent length of a simple pendulum.
Question 8
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The equivalent length of a simple pendulum which gives the same frequency as the compound pendulum is
h/ k2G +h2
k2G +h2/h
h2/k2G +h2
k2G +h2/h2
Explanation:
By comparing the frequencies of simple pendulum to compound pendulum we get the equivalent length of simple pendulum as k2G +h2/h.
Question 9
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The periodic time (tp) is given by
ω / 2 π
2 π / ω
2 π × ω
π/ω
Explanation:
Periodic time is the time taken for one complete revolution of the particle.
Question 10
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The frequency of oscillation of a torsional pendulum is
2πkG/r √g/I
r/2πkG√g/I
2πkG/r√I/g
r/2πkG√I/g
Explanation:
None.