Coefficient of Friction

Question 1
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Pass Ratio : 100%
A car moving with speed u can be stopped in minimum distance x when brakes are applied. If the speed becomes n times, the minimum distance over which the car can be stopped would take the value
x/n
nx
x/n2
n2x
Explanation:
x = u2/2g
Question 2
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A stone is projected horizontally from a cliff at 10 m/sec and lands on the ground below at 20 m from the base of the cliff. Find the height of the cliff.
18 m
20 m
22 m
24 m
Explanation:
h = 1/2at2
Question 3
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A car moving with uniform acceleration cover 450 m in a 5 second interval, and covers 700 m in the next 5 second interval. The acceleration of the car is
7 m/s2
50 m/s2
25 m/s2
10 m/s2
Explanation:
s = ut + 1/2at2
Question 4
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Which of the following statements regarding laws governing the friction between dry surfaces are correct?
The friction force is directly proportional to the normal force.
The friction force is dependent on the materials of the contact surfaces.
The friction force is independent of the area of contact.
all of the mentioned
Explanation:
Following are the laws of solid friction :
Question 5
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A particle starts with a velocity 2 m/sec and moves on a straight-line track with retardation 0.1 m/s2. The time at which the particle is 15 m from the startin g point would be
10 s
20 s
50 s
40 s
Explanation:
u = 2m/sec a = 0.1 m/sec
Question 6
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If two bodies one light and other heavy have equal kinetic energies, which one has a greater momentum
heavy body
light body
both have equal momentum
it depends on the actual velocities
Explanation:
1/2m1V12 = 1/2m2V22
Question 7
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Two particles with masses in the ratio 1 : 4 are moving with equal kinetic energies. The magnitude of their linear momentums will conform to the ratio
1 : 8
1 : 2
√2 : 1
√2
Explanation:
1/2m1V12 = 1/2m2V22
Question 8
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A heavy block of mass m is slowly placed on a conveyer belt moving with speed v. If coefficient of friction between block and the belt is μ, the block will slide on the belt through distance
v/μg
v2/√μg
(v/μg)2
v2/2μg
Explanation:
Retardation due to friction force = μg
Question 9
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Ratio of the radii of planes P1 and P2 is k and ratio of the accelerations due to gravity on them is s. Ratio of escape velocities from them will be
ks
√ks
√k/s
√s/k
Explanation:
v1/v2 = √g1/g2 √R2/R1
Question 10
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Pass Ratio : 100%
A block whose mass is 650 gm is fastened to aspring constant K equals 65 N/m whose other end is fixed. The block is pulled a distance x = 11 cm from its equilibrium position at x = 0 on a smooth surface, and released from rest at t = 0. The maximum speed ‘S’ of the oscillating block is
11 cm /sec
11 m/sec
11 mm/sec
1.1 m/sec
Explanation:
Maximum speed of the spring will be at x = 0, when total spring energy will be converted into kinematic energy of mass.