Differential equation of torque is given as T=j(dθ2(t)) / (dt2) and differential equation corresponding to force is given as F = M(dx2(t))/(dt2). Equating these two expressions we obtain mass ‘M’ and moment of inertia ‘j’ are equivalent quantities.

From transfer function of spring, it is clear that spring is a zero order system. Transfer function (F(s))/(G(s))=K.

Rate of change of velocity is acceleration and force can be described as product of mass and acceleration.

Static friction is a constant value and is the minimum force required to start motion of a body.

Mass M and Moment of inertia j are equivalent, thus transfer function of rotational motion can be obtained by replacing M with j.

Linear springs are used to provide restoring force and torsional springs are used to provide restoring torque respectively.

Restoring force of a spring under stress is given by KX(s), where K is the stiffness of spring and X(s) is the displacement made.

Transfer function of the viscous force is given as 1/sB, and the transfer function of the capacitor is given as 1/sC. On equating B and C becomes equivalent quantities.

Viscous friction acts when there is a relative motion between two bodies. It always acts opposite to direction of velocity.

Force can be described as the product of mass and acceleration, or in terms of displacement F = M(dx2 (t)) / (dt2). Converting to Laplace domain and finding transfer function we obtain the answer.