Digital Signal Processing

Design of IIR Filters in Frequency Domain

Question 1
Marks : +2 | -2
Pass Ratio : 17%
Filter parameter optimization technique is used for designing of which of the following?
FIR in time domain
FIR in frequency domain
IIR in time domain
IIR in frequency domain
Explanation:
We describe a filter parameter optimization technique carried out in the frequency domain that is representative of frequency domain design methods.
Question 2
Marks : +2 | -2
Pass Ratio : 33%
In this type of designing, the system function of IIR filter is expressed in which form?
Parallel form
Cascade form
Mixed form
Any of the mentioned
Explanation:
The design is most easily carried out with the system function for the IIR filter expressed in the cascade form as
Question 3
Marks : +2 | -2
Pass Ratio : 17%
What is the error in magnitude at the frequency ωk?
G.A(ωk) + Ad(ωk)
G.A(ωk) – Ad(ωk)
G.A(ωk) – A(ωk)
None of the mentioned
Explanation:
The error in magnitude at the frequency ωk is G.A(ωk) – Ad(ωk) for 0 ≤ |ω| ≤ Ï€, where Ad(ωk) is the desired magnitude response at ωk.
Question 4
Marks : +2 | -2
Pass Ratio : 17%
We cannot choose any arbitrary function for the errors in magnitude and delay.
True
False
Explanation:
As a performance index for determining the filter parameters, one can choose any arbitrary function of the errors in magnitude and delay.
Question 5
Marks : +2 | -2
Pass Ratio : 17%
What does ‘p’ represents in the arbitrary function of error?
2K-dimension vector
3K-dimension vector
4K-dimension vector
None of the mentioned
Explanation:
In the error function ‘p’ denotes the 4K dimension vector of the filter coefficients.
Question 6
Marks : +2 | -2
Pass Ratio : 17%
If the error in delay is defined as Tg(ωk) – Tg(ω0) – Td(ωkk), then what is Tg(ω0)?
Filter delay at nominal frequency in stop band
Filter delay at nominal frequency in transition band
Filter delay at nominal frequency
Filter delay at nominal frequency in pass band
Explanation:
We are led to define the error in delay as Tg(ωk) – Tg(ω0) – Td(ωk), where Tg(ω0) is the filter delay at some nominal centre frequency in the pass band of the filter.
Question 7
Marks : +2 | -2
Pass Ratio : 33%
It is more convenient to deal with the envelope delay as a function of frequency.
True
False
Explanation:
Instead of dealing with the phase response Ï´(ω), it is more convenient to deal with the envelope delay as a function of frequency.
Question 8
Marks : +2 | -2
Pass Ratio : 33%
The choice of Td(ωk) for error in delay is complicated.
True
False
Explanation:
We know that the error in delay is defined as Tg(ωk) – Td(ωk). However, the choice of Td(ωk) for error in delay is complicated by the difficulty in assigning a nominal delay of the filter.
Question 9
Marks : +2 | -2
Pass Ratio : 17%
What is the error in delay at the frequency ωk?
Tg(ωk)-Td(ωk)
Tg(ωk)+Td(ωk)
Td(ωk)
None of the mentioned
Explanation:
Similarly as in the previous question, the error in delay at ωk is defined as Tg(ωk)-Td(ωk), where Td(ωk) is the desired delay response.
Question 10
Marks : +2 | -2
Pass Ratio : 17%
Which of the following gives the equation for envelope delay?
dÏ´(ω)/dω
Ï´(ω)
-dÏ´(ω)/dω
-Ï´(ω)
Explanation:
Instead of dealing with the phase response Ï´(ω), it is more convenient to deal with the envelope delay as a function of frequency, which is