Digital Signal Processing

A2D and D2A Converters

Question 1
Marks : +2 | -2
Pass Ratio : 100%
The difference between the unquantized x(n) and quantized xq(n) is known as ___________
Quantization coefficient
Quantization ratio
Quantization factor
Quantization error
Explanation:
Quantization error is the difference in the signal obtained after sampling i.e., x(n) and the signal obtained after quantization i.e., xq(n) at any instant of time.
Question 2
Marks : +2 | -2
Pass Ratio : 100%
What is the discrete-time signal obtained after sampling the analog signal x(t)=cos(2000*pi*t)+sin(5000*pi*t) at a sampling rate of 5000 samples/sec?
cos(2.5*pi*n)+sin(pi*n)
cos(0.4*pi*n)+sin(pi*n)
cos(2000*pi*n)+sin(5000*pi*n)
none of the mentioned
Explanation:
From the given analog signal, F1=1000Hz F2=2500Hz and Fs=5000Hz
Question 3
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is a digital-to-analog conversion process?
Staircase approximation
Linear interpolation
Quadratic interpolation
All of the mentioned
Explanation:
The process of joining in terms of steps is known as staircase approximation, connecting two samples by a straight line is known as Linear interpolation, connecting three samples by fitting a quadratic curve is called as Quadratic interpolation.
Question 4
Marks : +2 | -2
Pass Ratio : 100%
If ‘F’ is the frequency of the analog signal, then what is the minimum sampling rate required to avoid aliasing?
F
2F
3F
4F
Explanation:
According to Nyquist rate, to avoid aliasing the sampling frequency should be equal to twice of the analog frequency.
Question 5
Marks : +2 | -2
Pass Ratio : 100%
What is the nyquist rate of the signal x(t)=3cos(50*pi*t)+10sin(300*pi*t)-cos(100*pi*t)?
50Hz
100Hz
200Hz
300Hz
Explanation:
The frequencies present in the given signal are F1=25Hz, F2=150Hz, F3=50Hz
Question 6
Marks : +2 | -2
Pass Ratio : 100%
The process of converting discrete-time continuous valued signal into discrete-time discrete valued (digital) signal is known as ____________
Sampling
Quantization
Coding
None of the mentioned
Explanation:
In this process, the value of each signal sample is represented by a value selected from a finite set of possible values. Hence this process is known as ‘quantization’
Question 7
Marks : +2 | -2
Pass Ratio : 100%
Which of the following should be done in order to convert a continuous-time signal to a discrete-time signal?
Sampling
Differentiating
Integrating
None of the mentioned
Explanation:
The process of converting a continuous-time signal into a discrete-time signal by taking samples of continuous time signal at discrete time instants is known as ‘sampling’.
Question 8
Marks : +2 | -2
Pass Ratio : 100%
What is output signal when a signal x(t)=cos(2*pi*40*t) is sampled with a sampling frequency of 20Hz?
cos(pi*n)
cos(2*pi*n)
cos(4*pi*n)
cos(8*pi*n)
Explanation:
From the question F=40Hz, Fs=20Hz
Question 9
Marks : +2 | -2
Pass Ratio : 100%
The relation between analog frequency ‘F’ and digital frequency ‘f’ is?
F=f*T(where T is sampling period)
f=F*T
No relation
None of the mentioned
Explanation:
Consider an analog signal of frequency ‘F’, which when sampled periodically at a rate Fs=1/T samples per second yields a frequency of f=F/Fs=>f=F*T.
Question 10
Marks : +2 | -2
Pass Ratio : 100%
If the sampling rate Fs satisfies the sampling theorem, then the relation between quantization errors of analog signal(eq(t)) and discrete-time signal(eq(n)) is?
eq(t)=eq(n)
eq(t)<eq(n)
eq(t)>eq(n)
not related
Explanation:
If it obeys sampling theorem, then the only error in A/D conversion is quantization error. So, the error is same for both analog and discrete-time signal.