Compilers

Symbol Table Organization

Question 1
Marks : +2 | -2
Pass Ratio : 100%
A Stack-organised Computer uses instruction of __________
Indirect addressing
Two-addressing
Zero addressing
Index addressing
Explanation:
Zero addressing modes are used in stack organised computer.
Question 2
Marks : +2 | -2
Pass Ratio : 100%
Cache memory acts between __________
CPU and RAM
RAM and ROM
CPU and Hard Disk
None of the mentioned
Explanation:
It acts between CPU and RAM.
Question 3
Marks : +2 | -2
Pass Ratio : 100%
Virtual memory consists of _________
Static RAM
Dynamic RAM
Magnetic memory
None of the mentioned
Explanation:
It does consist of static RAM.
Question 4
Marks : +2 | -2
Pass Ratio : 100%
Write Through technique is used in which memory for updating the data ___________
Virtual memory
Main memory
Auxiliary memory
Cache memory
Explanation:
The answer is cache memory.
Question 5
Marks : +2 | -2
Pass Ratio : 100%
_________ register keeps track of the instructions stored in program stored in memory.
AR (Address Register)
XR (Index Register)
PC (Program Counter)
AC (Accumulator)
Explanation:
Program Counter keeps track of the next instruction.
Question 6
Marks : +2 | -2
Pass Ratio : 100%
If the main memory is of 8K bytes and the cache memory is of 2K words. It uses associative mapping. Then each word of cache memory shall be __________
11 bits
21 bits
16 bits
20 bits
Explanation:
Each should be 8*2=16 bits.
Question 7
Marks : +2 | -2
Pass Ratio : 100%
An n-bit microprocessor has __________
n-bit program counter
n-bit address register
n-bit ALU
n-bit instruction register
Explanation:
N bit microprocessor has bit instruction register.
Question 8
Marks : +2 | -2
Pass Ratio : 100%
The circuit used to store one bit of data is known as __________
Encoder
OR gate
Flip Flop
Decoder
Explanation:
Flip flop is 1 bit circuit.
Question 9
Marks : +2 | -2
Pass Ratio : 100%
If memory access takes 20 ns with cache and 110 ns without it, then the ratio (cache uses a 10 ns memory) is __________
93%
90%
88%
87%
Explanation:
The answer is 90%.
Question 10
Marks : +2 | -2
Pass Ratio : 100%
In signed-magnitude binary division, if the dividend is (11100)2 and divisor is (10011)2 then the result is _________
(00100)2
(10100)2
(11001)2
(01100)2
Explanation:
After division we get 20 which is 10100.