Temperature

Question 1
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Pass Ratio : 100%
Let us say temperature of a body in degree Celsius and degree Rankine are related as TC = 50 + 3TR, what is the change in temperature in Kelvin, if the change in temperature in degree Rankine is 100oR?
300 K
180 K
100 K
90 K
Explanation:
∆TC = 3∆TR, => ∆TC = 3*100 = 300oC, => ∆TK = ∆TC = 300 K.
Question 2
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Which of the following is not a unit of temperature?
Celsius
Fahrenheit
Therm
Rankine
Explanation:
Them is a unit of energy, 1 therm = 105 BTU.
Question 3
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If change in temperate is 180 degree Rankine, what is the change in temperature in degree Celsius?
100oC
180oC
212oC
273oC
Explanation:
∆TR = 1.8∆TC, => Change in temperature = 180/1.8 = 100oC.
Question 4
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Which of the following is greatest?
10oC
10oR
10oF
10 K
Explanation:
10oC = 283 K = 50oF = 510oR, => 10oC is greatest.
Question 5
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Volume of an object is dependent upon its temperature in degree Celsius as V = a + bTC, what is the dependence of volume upon temperature in degree Rankine?
V = a + 32b + 9bTR/5
V = a + 492b + 9bTR/5
V = a + 492b + 5bTR/9
None of the mentioned
Explanation:
TC = 492 + 9TR/5, => V = a + b(492 + 9TR/5), => V = a + 492b + 9bTR/5.
Question 6
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Mass and volume of an object is dependent on its temperature in kelvin as m = 5t2 kg and v = (400 + 600t) m3 respectively, then what is the density of the object at t = 27oC?
5 kg/m3
10 kg/m3
15 kg/m3
20 kg/m3
Explanation:
Density of object = dm/dv = (dm/dt)/(dv/dt) = 10t/600 = t/60, => density of object at t = 27oC = 300 K is D = 300/60 = 5 kg/m3.
Question 7
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What is the value of 100oC in degree Fahrenheit?
212oF
460oF
672oF
884oF
Explanation:
TF = (9/5)100 + 32 = 212oF.
Question 8
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Absolute zero temperature is approximately equal to?
-160oR
-273oR
-373oR
-460oR
Explanation:
Absolute zero temperature = 0 K = -273oC = -460oR.
Question 9
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What is the value of 273 K in degree Rankine?
0oR
32oR
492oR
672oR
Explanation:
TR = (9/5)(273 – 273) + 492 = 492oR.
Question 10
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If change in temperate is 212 degree Fahrenheit, what is the change in temperature in degree Rankine?
100oR
212oR
273oR
460oR
Explanation:
Since ∆TR = ∆TF, => 212oF = 212oR.