Chemical Engineering

Ideal Gas Law

Question 1
Marks : +2 | -2
Pass Ratio : 100%
Which of the following term does not involve in ideal gas law?
Pressure
Volume
Temperature
Time
Explanation:
Ideal gas law is PV = nRT, which does not involve time.
Question 2
Marks : +2 | -2
Pass Ratio : 100%
What is the Temperature of a 2 liter/mole ideal gas with pressure 10 atm?
243.6 K
268.4 K
289.1 K
313.5 K
Explanation:
PV = nRT, => 10*2 = 0.0821*T, => T = 243.6 K.
Question 3
Marks : +2 | -2
Pass Ratio : 100%
What is the shape of a V-T curve for ideal gas?
Straight line
Parabolic
Hyperbolic
Ellipse
Explanation:
V-T curve is straight line for ideal gas.
Question 4
Marks : +2 | -2
Pass Ratio : 100%
What is the density of O2 at 27oC with pressure 1 atm?
1.1 g/L
1.3 g/L
1.5 g/L
1.7 g/L
Explanation:
Molecular wt. of O2= 44 g, PV = nRT, => PV = (m/M)RT, => d = PM/RT = (1*32)/(0.0821*300) = 1.3 g/L.
Question 5
Marks : +2 | -2
Pass Ratio : 100%
What is the shape of a P-T curve for ideal gas?
Straight line
Parabolic
Hyperbolic
Ellipse
Explanation:
P-T curve is a straight line for ideal gas.
Question 6
Marks : +2 | -2
Pass Ratio : 100%
What is the shape of a P-V curve for an ideal gas?
Straight line
Parabolic
Hyperbolic
Ellipse
Explanation:
P-V curve is hyperbolic for an ideal gas.
Question 7
Marks : +2 | -2
Pass Ratio : 100%
What is the pressure of a 5 liter/mole ideal gas at temperature 27oC?
2.5 atm
3.8 atm
4.4 atm
5.3 atm
Explanation:
PV = nRT, => P*5 = 0.0821*300, => P = 5.3 atm.
Question 8
Marks : +2 | -2
Pass Ratio : 100%
First of the two ideal gases has twice molar volume as much as the second at same temperature, what is the ratio of their pressures?
4:1
1:4
2:1
1:2
Explanation:
P1V1 = n1RT1, P2V2 = n2RT2 dividing both the equations, => P1:P2 = 1:2.
Question 9
Marks : +2 | -2
Pass Ratio : 100%
Which of the following is not true about ideal gas molecules?
They have negligible size
They do not have attractive forces
They do not apply pressure
They move in random motion
Explanation:
Ideal gas molecules apply pressure to the walls of a container.
Question 10
Marks : +2 | -2
Pass Ratio : 100%
88 grams of CO2 at 27oC is applying 5 atm pressure, what is the volume occupied by it?
5.6 liter
7.9 liter
9.8 liter
12.2 liter
Explanation:
n = 88/44 = 2, PV = nRT, => 5*V = 2*0.0821*300, => V = 9.8 liter.